Archive for May, 2008

Your Domain Name in XAMPP

May 4, 2008

This probably applies to many other things while working with XAMPP or any webserver on your machine, but I specifically used it when using AJAX. Just determine your LAN/local/internal ip address and use that ip address as your domain name. For example, if this is what you had on another webserver,

var myDomain = ""; //where your proxy file is placed
var proxy_name = "phpProxy.php";  //proxy's filename
var actualReq = "" //actual request
var url = "http://"+myDomain+proxy_name+"/?"+actualReq;

and your local ip for example is, replace


Also, when you call the file from your browser, instead of using “http://localhost/….”, use “….” instead.

Happy XAMPPing!


PHP Proxy for Cross-Domain Requests That Works!

May 3, 2008

So I’ve been working on some AJAX stuff, dealing with Yahoo! Weather, specifically, and I realized I needed some way to make cross domain xmlhttprequests. Using a PHP Proxy seemed for me to be the easiest way to go, so I first tried what was suggested by Yahoo! I then tried some similar methods from others here and here, both to no avail. I then did some asking around on forums and made the necessary changes to make Yahoo’s example work. Just thought I’d share that with those of you who have similar troubles.

This is the PHP Proxy that I used. Note that:

  1. Your webserver’s PHP needs to support cURL
  2. This code doesn’t support POST requests, only GET.
// PHP Proxy example for Yahoo! Web services.
// Responds to both HTTP GET and POST requests
// Author: Jason Levitt
// December 7th, 2005
//(Modified by Suan-Aik Yeo)
$url = $path;
// Open the Curl session
$session = curl_init($url);
// Don't return HTTP headers. Do return the contents of the call
curl_setopt($session, CURLOPT_HEADER, false);
curl_setopt($session, CURLOPT_RETURNTRANSFER, true);
// Make the call
$xml = curl_exec($session);
// The web service returns XML. Set the Content-Type appropriately
header("Content-Type: text/xml");
echo $xml;

When you’re using javascript to actually make the request, do something like this:

var proxy_name = "phpProxy.php";  //proxy's filename
var actualReq = ""; //actual request
var myDomain = ""; //where your proxy file is placed
var url = "http://"+myDomain+proxy_name+"/?"+actualReq;

//go on to do the usual httprequest steps...

Hope this helps!